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Learner I


Answers
2. Repeat the wordlist iterations, updating the frequency dictionary as necessary. Add one more frequency point if a term appears in the dictionary already. Add it to the dictionary with a frequency of 1 if it isn't already there.
3. Make a fresh wordlist by eliminating terms with a frequency below one. Repeat the process using the original wordlist, only include words that have a frequency in the frequency dictionary that is greater than or equal to 1.
Here's a Python code example to demonstrate this process:
from collections import defaultdict def remove_infrequent_words(wordlist): # Step 1: Create frequency dictionary frequency_dict = defaultdict(int) for word in wordlist: frequency_dict[word] += 1 # Step 3: Create new wordlist new_wordlist = [] for word in wordlist: if frequency_dict[word] >= 1: new_wordlist.append(word) return new_wordlist # Example usage wordlist = ["apple", "banana", "apple", "orange", "grape"] filtered_wordlist = remove_infrequent_words(wordlist) print(filtered_wordlist)
Vivek Garg
React Native