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Replace (Dictionary) operator has problem

kazemi_asghar
kazemi_asghar Member Posts: 8 image Learner I
in Help
hi.
i want to replace some codes whit cities name's.but i have a problem.
for example imagine this:
1----> A
2----> B
12----> C
but when i run my process instead of replacing "12" whit "C", it replaces "12" whit "AB"
I would appreciate it if help me.




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Answers

  • MartinLiebig
    MartinLiebig Administrator, Moderator, Employee-RapidMiner, RapidMiner Certified Analyst, RapidMiner Certified Expert, University Professor Posts: 3,533 image RM Data Scientist
    Hi,
    I think you want to use the Map operator and not Replace? Replace is to be used with regular expressions.

    Best,
    Martin
    - Sr. Director Data Solutions, Altair RapidMiner -
    Dortmund, Germany
  • kazemi_asghar
    kazemi_asghar Member Posts: 8 image Learner I
    @mschmitz i exactly want to use replace(dictionary) operator and it doesn't work properly.

  • MartinLiebig
    MartinLiebig Administrator, Moderator, Employee-RapidMiner, RapidMiner Certified Analyst, RapidMiner Certified Expert, University Professor Posts: 3,533 image RM Data Scientist
    Hi,
    okay, so you want to use regular expressions to replace parts of strings?
    ~Martin
    - Sr. Director Data Solutions, Altair RapidMiner -
    Dortmund, Germany
  • kazemi_asghar
    kazemi_asghar Member Posts: 8 image Learner I
    i can't understand you but hear is my examples:
    1 آذربایجان شرقی


    2 آذربایجان غربی


    3 اردبیل


    4 اصفهان


    5 البرز


    6 ایلام


    7 بوشهر


    8 تهران


    9 جنوب کرمان(جیرفت و کهنوج)


    10 چهار محال و بختیاری


    11 خراسان جنوبی


    12 خراسان رضوی


    13 خراسان شمالی


    14 خوزستان


    15 زنجان


    16 مازندران(ساری)


    17 سمنان


    18 سیستان و بلوچستان


    19 فارس


    20 قزوین


    and i want to replace numbers whit city names in another attribute. so operator replace,for example, number 15 with combination of 1 and 5.
  • kayman
    kayman Member Posts: 662 image Unicorn
    Replace your numbers as follows : \b1\b, so 12 becomes \b12\b

    This way the system knows it needs to replace the full number (12), and not 1 and 2 as that would be the default otherwise. 

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